Mits5003 Wireless Network And Communication 3119389

Given data is
fc = 500 kHz, fd = 25 kHz, M = 16 and L = 4 bits
fi=fc + (2i – 1 – M) *fd
M=2^L =2^4 = 16, M=16
0000 where i=1 then f1= 125KHz
0001 where i=2 then f2= 175KHZ
0010 where i=3 then f3= 225KHZ
0011 where i=4 then f4= 275KHz
0100 where i=5 then f5= 325KHz
0101 where i=6 then f6= 375KHz
0110 where i=7 then f7= 425KHz
0111 where i=8 then f8=475KHz
1000 where i=9 then f9=525KHz
1001 where i=10 then f10= 575KHz
1010 where i=11 then f11= 625KHz

Attachments:

Assignment-2…..docxassign2Skelet….zip

Prof. Angela

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